यदि (f(x)=x-2+1) और (g(x)=x-2-1) हैं, तो \(\frac{f+g}{f-g}\) का सरल रूप क्या है?

If (f(x)=x-2+1) and (g(x)=x-2-1), what is the simplified form of \(\frac{f+g}{f-g}\)?

Explanation opens after your attempt
Correct Answer

A. \(x^2\)

Step 1

Concept

Here \(f+g=2x^2\) and (f-g=2), so the ratio is \(x^2\). First find (f+g) and (f-g) separately.

Step 2

Why this answer is correct

The correct answer is A. \(x^2\). Here \(f+g=2x^2\) and (f-g=2), so the ratio is \(x^2\). First find (f+g) and (f-g) separately.

Step 3

Exam Tip

\(f+g=2x^2\) और (f-g=2), इसलिए अनुपात \(x^2\) है। पहले (f+g) और (f-g) अलग-अलग निकालें।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x-2+1) और (g(x)=x-2-1) हैं, तो \(\frac{f+g}{f-g}\) का सरल रूप क्या है? / If (f(x)=x-2+1) and (g(x)=x-2-1), what is the simplified form of \(\frac{f+g}{f-g}\)?

Correct Answer: A. \(x^2\). Explanation: \(f+g=2x^2\) और (f-g=2), इसलिए अनुपात \(x^2\) है। पहले (f+g) और (f-g) अलग-अलग निकालें। / Here \(f+g=2x^2\) and (f-g=2), so the ratio is \(x^2\). First find (f+g) and (f-g) separately.

Which concept should I revise for this Mathematics MCQ?

Here \(f+g=2x^2\) and (f-g=2), so the ratio is \(x^2\). First find (f+g) and (f-g) separately.

What exam hint can help solve this Mathematics question?

\(f+g=2x^2\) और (f-g=2), इसलिए अनुपात \(x^2\) है। पहले (f+g) और (f-g) अलग-अलग निकालें।