यदि (f(x)=x-2-1) और (g(x)=x-2+1) हैं तो ((g-f)(x)) कौन सा फलन है?

If (f(x)=x-2-1) and (g(x)=x-2+1) then what type of function is ((g-f)(x))?

Explanation opens after your attempt
Correct Answer

A. स्थिर फलनConstant function

Step 1

Concept

((g-f)(x)=x-2+1-\(x^2-1\)=2), so it is a constant function. Equal highest-degree terms may cancel.

Step 2

Why this answer is correct

The correct answer is A. स्थिर फलन / Constant function. ((g-f)(x)=x-2+1-\(x^2-1\)=2), so it is a constant function. Equal highest-degree terms may cancel.

Step 3

Exam Tip

((g-f)(x)=x-2+1-\(x^2-1\)=2), इसलिए यह स्थिर फलन है। समान उच्च घात पद कट सकते हैं।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x-2-1) और (g(x)=x-2+1) हैं तो ((g-f)(x)) कौन सा फलन है? / If (f(x)=x-2-1) and (g(x)=x-2+1) then what type of function is ((g-f)(x))?

Correct Answer: A. स्थिर फलन / Constant function. Explanation: ((g-f)(x)=x-2+1-\(x^2-1\)=2), इसलिए यह स्थिर फलन है। समान उच्च घात पद कट सकते हैं। / ((g-f)(x)=x-2+1-\(x^2-1\)=2), so it is a constant function. Equal highest-degree terms may cancel.

Which concept should I revise for this Mathematics MCQ?

((g-f)(x)=x-2+1-\(x^2-1\)=2), so it is a constant function. Equal highest-degree terms may cancel.

What exam hint can help solve this Mathematics question?

((g-f)(x)=x-2+1-\(x^2-1\)=2), इसलिए यह स्थिर फलन है। समान उच्च घात पद कट सकते हैं।