यदि (f(x)=\sqrt{x}) और (g(x)=\frac{1}{x-4}) हैं, तो (f+g) का डोमेन क्या होगा?

If (f(x)=\sqrt{x}) and (g(x)=\frac{1}{x-4}), what is the domain of (f+g)?

Explanation opens after your attempt
Correct Answer

A. \( [0,\infty\)-{4} )

Step 1

Concept

For \(\sqrt{x}\), \(x\ge0\), and for \(\frac{1}{x-4}\), \(x\neq4\). Hence the domain is \( [0,\infty\)-{4} ).

Step 2

Why this answer is correct

The correct answer is A. \( [0,\infty\)-{4} ). For \(\sqrt{x}\), \(x\ge0\), and for \(\frac{1}{x-4}\), \(x\neq4\). Hence the domain is \( [0,\infty\)-{4} ).

Step 3

Exam Tip

\(\sqrt{x}\) के लिए \(x\ge0\) और \(\frac{1}{x-4}\) के लिए \(x\neq4\) चाहिए। इसलिए डोमेन \( [0,\infty\)-{4} ) है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{x}) और (g(x)=\frac{1}{x-4}) हैं, तो (f+g) का डोमेन क्या होगा? / If (f(x)=\sqrt{x}) and (g(x)=\frac{1}{x-4}), what is the domain of (f+g)?

Correct Answer: A. \( [0,\infty\)-{4} ). Explanation: \(\sqrt{x}\) के लिए \(x\ge0\) और \(\frac{1}{x-4}\) के लिए \(x\neq4\) चाहिए। इसलिए डोमेन \( [0,\infty\)-{4} ) है। / For \(\sqrt{x}\), \(x\ge0\), and for \(\frac{1}{x-4}\), \(x\neq4\). Hence the domain is \( [0,\infty\)-{4} ).

Which concept should I revise for this Mathematics MCQ?

For \(\sqrt{x}\), \(x\ge0\), and for \(\frac{1}{x-4}\), \(x\neq4\). Hence the domain is \( [0,\infty\)-{4} ).

What exam hint can help solve this Mathematics question?

\(\sqrt{x}\) के लिए \(x\ge0\) और \(\frac{1}{x-4}\) के लिए \(x\neq4\) चाहिए। इसलिए डोमेन \( [0,\infty\)-{4} ) है।