यदि (f(x)=\frac{x-2}{x+2}) और (g(x)=\frac{x+2}{x-2}) हैं तो ((f+g)(x)) का प्रांत क्या है?

If (f(x)=\frac{x-2}{x+2}) and (g(x)=\frac{x+2}{x-2}) then what is the domain of ((f+g)(x))?

Explanation opens after your attempt
Correct Answer

A. \(\mathbb{R}-{-2,2})

Step 1

Concept

The first function needs \(x\ne -2\) and the second needs \(x\ne 2\). The domain of the sum is obtained by excluding both restrictions.

Step 2

Why this answer is correct

The correct answer is A. \(\mathbb{R}-{-2,2}). The first function needs \(x\ne -2\) and the second needs \(x\ne 2\). The domain of the sum is obtained by excluding both restrictions.

Step 3

Exam Tip

पहले फलन में \(x\ne -2\) और दूसरे में \(x\ne 2\) है। योग का प्रांत दोनों प्रतिबंधों को हटाकर मिलेगा।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\frac{x-2}{x+2}) और (g(x)=\frac{x+2}{x-2}) हैं तो ((f+g)(x)) का प्रांत क्या है? / If (f(x)=\frac{x-2}{x+2}) and (g(x)=\frac{x+2}{x-2}) then what is the domain of ((f+g)(x))?

Correct Answer: A. \(\mathbb{R}-{-2,2}). Explanation: पहले फलन में \(x\ne -2\) और दूसरे में \(x\ne 2\) है। योग का प्रांत दोनों प्रतिबंधों को हटाकर मिलेगा। / The first function needs \(x\ne -2\) and the second needs \(x\ne 2\). The domain of the sum is obtained by excluding both restrictions.

Which concept should I revise for this Mathematics MCQ?

The first function needs \(x\ne -2\) and the second needs \(x\ne 2\). The domain of the sum is obtained by excluding both restrictions.

What exam hint can help solve this Mathematics question?

पहले फलन में \(x\ne -2\) और दूसरे में \(x\ne 2\) है। योग का प्रांत दोनों प्रतिबंधों को हटाकर मिलेगा।