Class 11 Mathematics Relations and Functions Real valued functions, domain and range of these functions Hard Level 33

यदि (f(x)=\frac{x-2+1}{x-2-1}), तो प्रांत क्या है?

If (f(x)=\frac{x-2+1}{x-2-1}), what is the domain?

Explanation opens after your attempt
Correct Answer

A. \(\mathbb{R}-{-1,1}\)

Step 1

Concept

The denominator must satisfy \(x^2-1\ne 0\). Therefore \(x\ne -1\) and \(x\ne 1\).

Step 2

Why this answer is correct

The correct answer is A. \(\mathbb{R}-{-1,1}\). The denominator must satisfy \(x^2-1\ne 0\). Therefore \(x\ne -1\) and \(x\ne 1\).

Step 3

Exam Tip

हर \(x^2-1\ne 0\) होना चाहिए। इसलिए \(x\ne -1\) और \(x\ne 1\)।

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यदि (f(x)=\frac{x-2+1}{x-2-1}), तो प्रांत क्या है? / If (f(x)=\frac{x-2+1}{x-2-1}), what is the domain?

Correct Answer: A. \(\mathbb{R}-{-1,1}\). Explanation: हर \(x^2-1\ne 0\) होना चाहिए। इसलिए \(x\ne -1\) और \(x\ne 1\)। / The denominator must satisfy \(x^2-1\ne 0\). Therefore \(x\ne -1\) and \(x\ne 1\).

Which concept should I revise for this Mathematics MCQ?

The denominator must satisfy \(x^2-1\ne 0\). Therefore \(x\ne -1\) and \(x\ne 1\).

What exam hint can help solve this Mathematics question?

हर \(x^2-1\ne 0\) होना चाहिए। इसलिए \(x\ne -1\) और \(x\ne 1\)।