यदि (f(x)=\frac{1}{x-2-4}) और (g(x)=\frac{1}{x-2}) हों, तो ((f-g)(x)) का प्रांत क्या होगा?
If (f(x)=\frac{1}{x-2-4}) and (g(x)=\frac{1}{x-2}), what is the domain of ((f-g)(x))?
Explanation opens after your attempt
Correct Answer
A. \( \mathbb{R}\setminus{-2,2} \)
Concept
The first function gives \(x^2-4\ne 0\), so \(x\ne \pm2\), and the second gives \(x\ne 2\). The common domain is \( \mathbb{R}\setminus{-2,2} \).
Why this answer is correct
The correct answer is A. \( \mathbb{R}\setminus{-2,2} \). The first function gives \(x^2-4\ne 0\), so \(x\ne \pm2\), and the second gives \(x\ne 2\). The common domain is \( \mathbb{R}\setminus{-2,2} \).
Exam Tip
पहले फलन में \(x^2-4\ne 0\) से \(x\ne \pm2\), और दूसरे में \(x\ne 2\)। संयुक्त प्रांत \( \mathbb{R}\setminus{-2,2} \) है।
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