यदि (f(x)=\frac{1}{\sqrt{x-1}}) और (g(x)=\sqrt{4-x}) हैं, तो (f+g) का डोमेन क्या होगा?

If (f(x)=\frac{1}{\sqrt{x-1}}) and (g(x)=\sqrt{4-x}), what is the domain of (f+g)?

Explanation opens after your attempt
Correct Answer

A. ( (1,4] )

Step 1

Concept

For \(\frac{1}{\sqrt{x-1}}\), (x>1), and for \(\sqrt{4-x}\), \(x\le4\). Thus the common domain is ( (1,4] ).

Step 2

Why this answer is correct

The correct answer is A. ( (1,4] ). For \(\frac{1}{\sqrt{x-1}}\), (x>1), and for \(\sqrt{4-x}\), \(x\le4\). Thus the common domain is ( (1,4] ).

Step 3

Exam Tip

\(\frac{1}{\sqrt{x-1}}\) के लिए (x>1) और \(\sqrt{4-x}\) के लिए \(x\le4\) चाहिए। अतः साझा डोमेन ( (1,4] ) है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\frac{1}{\sqrt{x-1}}) और (g(x)=\sqrt{4-x}) हैं, तो (f+g) का डोमेन क्या होगा? / If (f(x)=\frac{1}{\sqrt{x-1}}) and (g(x)=\sqrt{4-x}), what is the domain of (f+g)?

Correct Answer: A. ( (1,4] ). Explanation: \(\frac{1}{\sqrt{x-1}}\) के लिए (x>1) और \(\sqrt{4-x}\) के लिए \(x\le4\) चाहिए। अतः साझा डोमेन ( (1,4] ) है। / For \(\frac{1}{\sqrt{x-1}}\), (x>1), and for \(\sqrt{4-x}\), \(x\le4\). Thus the common domain is ( (1,4] ).

Which concept should I revise for this Mathematics MCQ?

For \(\frac{1}{\sqrt{x-1}}\), (x>1), and for \(\sqrt{4-x}\), \(x\le4\). Thus the common domain is ( (1,4] ).

What exam hint can help solve this Mathematics question?

\(\frac{1}{\sqrt{x-1}}\) के लिए (x>1) और \(\sqrt{4-x}\) के लिए \(x\le4\) चाहिए। अतः साझा डोमेन ( (1,4] ) है।