यदि \(f:\mathbb{R}\to\mathbb{R}\) को (f(x)=\frac{x-2+9}{x-2+3}) से दिया गया है, तो परिसर क्या है?
If \(f:\mathbb{R}\to\mathbb{R}\) is given by (f(x)=\frac{x-2+9}{x-2+3}), what is the range?
Explanation opens after your attempt
Correct Answer
A. ((1,3])
Concept
Since (f(x)=1+\frac{6}{x-2+3}), the maximum is (3), and (1) is never reached. The range is ((1,3]).
Why this answer is correct
The correct answer is A. ((1,3]). Since (f(x)=1+\frac{6}{x-2+3}), the maximum is (3), and (1) is never reached. The range is ((1,3]).
Exam Tip
(f(x)=1+\frac{6}{x-2+3}), इसलिए अधिकतम (3) है और (1) कभी नहीं मिलता। परिसर ((1,3]) है।
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