यदि \(f:\mathbb{R}\to\mathbb{R}\) को (f(x)=\frac{x-2+4}{x-2+1}) से दिया गया है, तो परिसर क्या है?
If \(f:\mathbb{R}\to\mathbb{R}\) is given by (f(x)=\frac{x-2+4}{x-2+1}), what is the range?
Explanation opens after your attempt
Correct Answer
A. ((1,4])
Concept
Since (f(x)=1+\frac{3}{x-2+1}), the maximum is (4) and (1) is never reached. The range is ((1,4]).
Why this answer is correct
The correct answer is A. ((1,4]). Since (f(x)=1+\frac{3}{x-2+1}), the maximum is (4) and (1) is never reached. The range is ((1,4]).
Exam Tip
(f(x)=1+\frac{3}{x-2+1}), इसलिए अधिकतम (4) है और (1) कभी नहीं मिलता। परिसर ((1,4]) है।
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