यदि \(\binom{n}{0}+\binom{n}{n}=2\) है तो यह किस प्रकार की पहचान दिखाता है?

If \(\binom{n}{0}+\binom{n}{n}=2\), what type of identity does it show?

Explanation opens after your attempt
Correct Answer

A. सीमा पहचानBoundary identity

Step 1

Concept

Because \(\binom{n}{0}=1\) and \(\binom{n}{n}=1\). This is a boundary identity of combinations.

Step 2

Why this answer is correct

The correct answer is A. सीमा पहचान / Boundary identity. Because \(\binom{n}{0}=1\) and \(\binom{n}{n}=1\). This is a boundary identity of combinations.

Step 3

Exam Tip

क्योंकि \(\binom{n}{0}=1\) और \(\binom{n}{n}=1\) होते हैं। यह संयोजन की सीमा पहचान है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(\binom{n}{0}+\binom{n}{n}=2\) है तो यह किस प्रकार की पहचान दिखाता है? / If \(\binom{n}{0}+\binom{n}{n}=2\), what type of identity does it show?

Correct Answer: A. सीमा पहचान / Boundary identity. Explanation: क्योंकि \(\binom{n}{0}=1\) और \(\binom{n}{n}=1\) होते हैं। यह संयोजन की सीमा पहचान है। / Because \(\binom{n}{0}=1\) and \(\binom{n}{n}=1\). This is a boundary identity of combinations.

Which concept should I revise for this Mathematics MCQ?

Because \(\binom{n}{0}=1\) and \(\binom{n}{n}=1\). This is a boundary identity of combinations.

What exam hint can help solve this Mathematics question?

क्योंकि \(\binom{n}{0}=1\) और \(\binom{n}{n}=1\) होते हैं। यह संयोजन की सीमा पहचान है।