यदि \(A={x:x\) संख्या (18) की धनात्मक भाजक है(}), तो (n(\mathcal{P}(A))) क्या होगा?
If \(A={x:x\) is a positive divisor of (18)(}), what is (n(\mathcal{P}(A)))?
Explanation opens after your attempt
Correct Answer
C. (64)
Concept
The positive divisors of (18) are (1,2,3,6,9,18), so (n(A)=6). Hence (n(\mathcal{P}(A))=26=64).
Why this answer is correct
The correct answer is C. (64). The positive divisors of (18) are (1,2,3,6,9,18), so (n(A)=6). Hence (n(\mathcal{P}(A))=26=64).
Exam Tip
(18) के धनात्मक भाजक (1,2,3,6,9,18) हैं, इसलिए (n(A)=6)। अतः (n(\mathcal{P}(A))=26=64)।
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