यदि \(A={x:x\) अंग्रेजी शब्द (LEVEL) के अलग-अलग अक्षर हैं(}), तो (\mathcal{P}(A)) में कितने तत्व होंगे?
If \(A={x:x\) is a distinct letter of the English word (LEVEL)(}), how many elements will (\mathcal{P}(A)) have?
Explanation opens after your attempt
Correct Answer
A. (8)
Concept
The distinct letters of (LEVEL) are (L,E,V), so (n(A)=3). Therefore the power set has \(2^3=8\) elements.
Why this answer is correct
The correct answer is A. (8). The distinct letters of (LEVEL) are (L,E,V), so (n(A)=3). Therefore the power set has \(2^3=8\) elements.
Exam Tip
(LEVEL) के अलग-अलग अक्षर (L,E,V) हैं, इसलिए (n(A)=3)। अतः घात समुच्चय में \(2^3=8\) तत्व होंगे।
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