यदि \(A={x:x\in\mathbb{R},;x^2-9=0}\) और \(B={x:x\in\mathbb{R},;x^2-6x+9=0}\), तो \(A\cup B\) क्या है?

If \(A={x:x\in\mathbb{R},;x^2-9=0}\) and \(B={x:x\in\mathbb{R},;x^2-6x+9=0}\), what is \(A\cup B\)?

Explanation opens after your attempt
Correct Answer

A. ({-3,3})

Step 1

Concept

First \(A=\{-3,3\}\) and \(B=\{3\}\). The union removes repetition and gives ({-3,3}).

Step 2

Why this answer is correct

The correct answer is A. ({-3,3}). First \(A=\{-3,3\}\) and \(B=\{3\}\). The union removes repetition and gives ({-3,3}).

Step 3

Exam Tip

पहले \(A=\{-3,3\}\) और \(B=\{3\}\) है। संघ में दोहराव हटाकर ({-3,3}) मिलता है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(A={x:x\in\mathbb{R},;x^2-9=0}\) और \(B={x:x\in\mathbb{R},;x^2-6x+9=0}\), तो \(A\cup B\) क्या है? / If \(A={x:x\in\mathbb{R},;x^2-9=0}\) and \(B={x:x\in\mathbb{R},;x^2-6x+9=0}\), what is \(A\cup B\)?

Correct Answer: A. ({-3,3}). Explanation: पहले \(A=\{-3,3\}\) और \(B=\{3\}\) है। संघ में दोहराव हटाकर ({-3,3}) मिलता है। / First \(A=\{-3,3\}\) and \(B=\{3\}\). The union removes repetition and gives ({-3,3}).

Which concept should I revise for this Mathematics MCQ?

First \(A=\{-3,3\}\) and \(B=\{3\}\). The union removes repetition and gives ({-3,3}).

What exam hint can help solve this Mathematics question?

पहले \(A=\{-3,3\}\) और \(B=\{3\}\) है। संघ में दोहराव हटाकर ({-3,3}) मिलता है।