यदि \(A={x:x\in\mathbb{R},\ 0\le x\le4}\) और \(B={x:x\in\mathbb{R},\ x^2-4x+3\le0}\), तो \(A\cap B\) क्या है?
If \(A={x:x\in\mathbb{R},\ 0\le x\le4}\) and \(B={x:x\in\mathbb{R},\ x^2-4x+3\le0}\), what is \(A\cap B\)?
Explanation opens after your attempt
Correct Answer
A. ([1,3])
Concept
\(x^2-4x+3\le0\) gives ([1,3]), which lies inside (A). Solve the quadratic inequality first, then intersect.
Why this answer is correct
The correct answer is A. ([1,3]). \(x^2-4x+3\le0\) gives ([1,3]), which lies inside (A). Solve the quadratic inequality first, then intersect.
Exam Tip
\(x^2-4x+3\le0\) से ([1,3]) मिलता है, जो (A) के अंदर है। द्विघात असमानता हल करके फिर प्रतिच्छेद लें।
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