यदि \(A={x:x\in\mathbb{N},;x\le 20,;x अभाज्य है}\) और (B={x:x\in\mathbb{N},;x\le 20,;x विषम है\(}), तो (A\setminus B) क्या है\)?
If \(A={x:x\in\mathbb{N},;x\le 20,;x is prime}\) and (B={x:x\in\mathbb{N},;x\le 20,;x is odd\(}), what is (A\setminus B)\)?
Explanation opens after your attempt
Correct Answer
A. ({2})
Concept
Only (2) is an even prime number up to (20). Therefore after removing odd numbers, ({2}) remains.
Why this answer is correct
The correct answer is A. ({2}). Only (2) is an even prime number up to (20). Therefore after removing odd numbers, ({2}) remains.
Exam Tip
(20) तक केवल (2) ही सम अभाज्य संख्या है। इसलिए विषम संख्याएँ हटाने पर ({2}) बचता है।
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