\(यदि (A={x:x\in \mathbb{N},x\le 20}), (B={x:x\) is odd\(,x\le 20}) और (C={x:x\) is a multiple of \(5,x\le 20}) है, तो (n(B\cap C)) कितना है\)?
\(If (A={x:x\in \mathbb{N},x\le 20}), (B={x:x\) is odd\(,x\le 20}) and (C={x:x\) is a multiple of \(5,x\le 20}), then what is (n(B\cap C))\)?
Explanation opens after your attempt
Correct Answer
A. (2)
Concept
\(B\cap C\) contains (5) and (15), so the count is (2). In set-builder form, check the conditions together.
Why this answer is correct
The correct answer is A. (2). \(B\cap C\) contains (5) and (15), so the count is (2). In set-builder form, check the conditions together.
Exam Tip
\(B\cap C\) में (5) और (15) आते हैं, इसलिए संख्या (2) है। समुच्चय-निर्माण रूप में शर्तों को एक साथ जाँचें।
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