यदि \(A\subseteq B\), (n(A)=52), (n(B)=91) और (n(U)=140) है, तो (n\((B-A)\cup B'\)) कितना होगा?
If \(A\subseteq B\), (n(A)=52), (n(B)=91) and (n(U)=140), then what is (n\((B-A)\cup B'\))?
Explanation opens after your attempt
Correct Answer
A. (88)
Concept
(B-A=91-52=39) and (B'=140-91=49), and these regions are disjoint, so the sum is (88). Identify separate regions in subset diagrams.
Why this answer is correct
The correct answer is A. (88). (B-A=91-52=39) and (B'=140-91=49), and these regions are disjoint, so the sum is (88). Identify separate regions in subset diagrams.
Exam Tip
(B-A=91-52=39) और (B'=140-91=49), ये अलग क्षेत्र हैं, इसलिए योग (88) है। उपसमुच्चय आरेख में क्षेत्रों को अलग पहचानें।
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