यदि (A) में (3) अवयव और (B) में (2) अवयव हैं, तो (A) से (B) तक कुल कितने संबंध संभव हैं?

If (A) has (3) elements and (B) has (2) elements, how many relations are possible from (A) to (B)?

Explanation opens after your attempt
Correct Answer

A. \(2^6\)

Step 1

Concept

(n\(A\times B\)=3\times2=6), and every relation is a subset of \(A\times B\). Therefore the number of relations is \(2^6\).

Step 2

Why this answer is correct

The correct answer is A. \(2^6\). (n\(A\times B\)=3\times2=6), and every relation is a subset of \(A\times B\). Therefore the number of relations is \(2^6\).

Step 3

Exam Tip

(n\(A\times B\)=3\times2=6), और हर संबंध \(A\times B\) का उपसमुच्चय है। इसलिए संबंधों की संख्या \(2^6\) होगी।

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Mathematics Answer, Explanation and Revision Hints

यदि (A) में (3) अवयव और (B) में (2) अवयव हैं, तो (A) से (B) तक कुल कितने संबंध संभव हैं? / If (A) has (3) elements and (B) has (2) elements, how many relations are possible from (A) to (B)?

Correct Answer: A. \(2^6\). Explanation: (n\(A\times B\)=3\times2=6), और हर संबंध \(A\times B\) का उपसमुच्चय है। इसलिए संबंधों की संख्या \(2^6\) होगी। / (n\(A\times B\)=3\times2=6), and every relation is a subset of \(A\times B\). Therefore the number of relations is \(2^6\).

Which concept should I revise for this Mathematics MCQ?

(n\(A\times B\)=3\times2=6), and every relation is a subset of \(A\times B\). Therefore the number of relations is \(2^6\).

What exam hint can help solve this Mathematics question?

(n\(A\times B\)=3\times2=6), और हर संबंध \(A\times B\) का उपसमुच्चय है। इसलिए संबंधों की संख्या \(2^6\) होगी।