यदि \(A\cap B=\varnothing\), (|A|=4), और (|B|=3) है, तो \(|\mathcal{P}(A)\cup\mathcal{P}(B)|\) कितना है?
If \(A\cap B=\varnothing\), (|A|=4), and (|B|=3), what is \(|\mathcal{P}(A)\cup\mathcal{P}(B)|\)?
Explanation opens after your attempt
C. (23)
Concept
The only common member of the two power sets is \(\varnothing\). Therefore \(2^4+2^3-1=16+8-1=23\).
Why this answer is correct
The correct answer is C. (23). The only common member of the two power sets is \(\varnothing\). Therefore \(2^4+2^3-1=16+8-1=23\).
Exam Tip
दोनों power sets में common member केवल \(\varnothing\) है। इसलिए \(2^4+2^3-1=16+8-1=23\)।
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