यदि \(A\cap B=\varnothing\), (|A|=3), और (|B|=4) है, तो \(|\mathcal{P}(A)\cap\mathcal{P}(B)|\) कितना है?
If \(A\cap B=\varnothing\), (|A|=3), and (|B|=4), what is \(|\mathcal{P}(A)\cap\mathcal{P}(B)|\)?
Explanation opens after your attempt
Correct Answer
B. (1)
Concept
When \(A\cap B=\varnothing\), the only common subset is \(\varnothing\). Therefore the cardinality is (1).
Why this answer is correct
The correct answer is B. (1). When \(A\cap B=\varnothing\), the only common subset is \(\varnothing\). Therefore the cardinality is (1).
Exam Tip
जब \(A\cap B=\varnothing\), तब common subset केवल \(\varnothing\) होता है। इसलिए cardinality (1) है।
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