यदि (8) distinct letters से (5)-letter word बनाना हो और repetition allowed न हो तो count को \(^{8}C_5\) से कैसे जोड़ेंगे?
If a (5)-letter word is made from (8) distinct letters without repetition, how is the count connected with \(^{8}C_5\)?
Explanation opens after your attempt
Correct Answer
A. \(^{8}C_5\times5!\)
Concept
First choose (5) letters and then arrange them in (5!) ways. In exams order is important in a word.
Why this answer is correct
The correct answer is A. \(^{8}C_5\times5!\). First choose (5) letters and then arrange them in (5!) ways. In exams order is important in a word.
Exam Tip
पहले (5) letters चुनते हैं और फिर उन्हें (5!) तरीकों से जमाते हैं। परीक्षा में word में order महत्वपूर्ण होता है।
Login to save your score, XP, coins and progress.