यदि \(A=\{1,2,5\}\), \(B=\{2,3,5\}\) और \(C=\{5,7\}\) हैं, तो (A\times\(B\cap C\)) में कितने अवयव होंगे?

If \(A=\{1,2,5\}\), \(B=\{2,3,5\}\) and \(C=\{5,7\}\), how many elements are there in (A\times\(B\cap C\))?

Explanation opens after your attempt
Correct Answer

A. (3)

Step 1

Concept

\(B\cap C={5}\), so (n(A\times\(B\cap C\))=3\times1=3). First find the intersection and then count the Cartesian product.

Step 2

Why this answer is correct

The correct answer is A. (3). \(B\cap C={5}\), so (n(A\times\(B\cap C\))=3\times1=3). First find the intersection and then count the Cartesian product.

Step 3

Exam Tip

\(B\cap C={5}\), इसलिए (n(A\times\(B\cap C\))=3\times1=3)। पहले प्रतिच्छेद निकालें फिर कार्तीय गुणन गिनें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{1,2,5\}\), \(B=\{2,3,5\}\) और \(C=\{5,7\}\) हैं, तो (A\times\(B\cap C\)) में कितने अवयव होंगे? / If \(A=\{1,2,5\}\), \(B=\{2,3,5\}\) and \(C=\{5,7\}\), how many elements are there in (A\times\(B\cap C\))?

Correct Answer: A. (3). Explanation: \(B\cap C={5}\), इसलिए (n(A\times\(B\cap C\))=3\times1=3)। पहले प्रतिच्छेद निकालें फिर कार्तीय गुणन गिनें। / \(B\cap C={5}\), so (n(A\times\(B\cap C\))=3\times1=3). First find the intersection and then count the Cartesian product.

Which concept should I revise for this Mathematics MCQ?

\(B\cap C={5}\), so (n(A\times\(B\cap C\))=3\times1=3). First find the intersection and then count the Cartesian product.

What exam hint can help solve this Mathematics question?

\(B\cap C={5}\), इसलिए (n(A\times\(B\cap C\))=3\times1=3)। पहले प्रतिच्छेद निकालें फिर कार्तीय गुणन गिनें।