\(यदि (A={1,2,3}), (B={1,2,3}) और (R={(x,y)\in A\times B:x+y\) is even}), तो (n(R)) क्या है?

\(If (A={1,2,3}), (B={1,2,3}), and (R={(x,y)\in A\times B:x+y\) is even}), what is (n(R))?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

The sum is even when both numbers have the same parity. Odd-odd gives (4) pairs and even-even gives (1), so total is (5).

Step 2

Why this answer is correct

The correct answer is C. (5). The sum is even when both numbers have the same parity. Odd-odd gives (4) pairs and even-even gives (1), so total is (5).

Step 3

Exam Tip

योग सम तब होगा जब दोनों संख्याएं समान समता की हों। विषम-विषम (4) और सम-सम (1) मिलकर कुल (5) युग्म देते हैं।

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Mathematics Answer, Explanation and Revision Hints

\(यदि (A={1,2,3}), (B={1,2,3}) और (R={(x,y)\in A\times B:x+y\) is even}), तो (n(R)) क्या है? \(/ If (A={1,2,3}), (B={1,2,3}), and (R={(x,y)\in A\times B:x+y\) is even}), what is (n(R))?

Correct Answer: C. (5). Explanation: योग सम तब होगा जब दोनों संख्याएं समान समता की हों। विषम-विषम (4) और सम-सम (1) मिलकर कुल (5) युग्म देते हैं। / The sum is even when both numbers have the same parity. Odd-odd gives (4) pairs and even-even gives (1), so total is (5).

Which concept should I revise for this Mathematics MCQ?

The sum is even when both numbers have the same parity. Odd-odd gives (4) pairs and even-even gives (1), so total is (5).

What exam hint can help solve this Mathematics question?

योग सम तब होगा जब दोनों संख्याएं समान समता की हों। विषम-विषम (4) और सम-सम (1) मिलकर कुल (5) युग्म देते हैं।