यदि \(A=\{1,2,3\}\) और \(B=\{4,5\}\) हों तो (A) से (B) तक कुल कितने संबंध बन सकते हैं?

If \(A=\{1,2,3\}\) and \(B=\{4,5\}\), how many total relations can be formed from (A) to (B)?

Explanation opens after your attempt
Correct Answer

C. (64)

Step 1

Concept

Since (n\(A\times B\)=3\times 2=6), the number of relations is \(2^6=64\). In exams, first count the elements of \(A\times B\).

Step 2

Why this answer is correct

The correct answer is C. (64). Since (n\(A\times B\)=3\times 2=6), the number of relations is \(2^6=64\). In exams, first count the elements of \(A\times B\).

Step 3

Exam Tip

क्योंकि (n\(A\times B\)=3\times 2=6) और संबंधों की संख्या \(2^6=64\) होती है। परीक्षा में पहले \(A\times B\) के अवयव गिनें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{1,2,3\}\) और \(B=\{4,5\}\) हों तो (A) से (B) तक कुल कितने संबंध बन सकते हैं? / If \(A=\{1,2,3\}\) and \(B=\{4,5\}\), how many total relations can be formed from (A) to (B)?

Correct Answer: C. (64). Explanation: क्योंकि (n\(A\times B\)=3\times 2=6) और संबंधों की संख्या \(2^6=64\) होती है। परीक्षा में पहले \(A\times B\) के अवयव गिनें। / Since (n\(A\times B\)=3\times 2=6), the number of relations is \(2^6=64\). In exams, first count the elements of \(A\times B\).

Which concept should I revise for this Mathematics MCQ?

Since (n\(A\times B\)=3\times 2=6), the number of relations is \(2^6=64\). In exams, first count the elements of \(A\times B\).

What exam hint can help solve this Mathematics question?

क्योंकि (n\(A\times B\)=3\times 2=6) और संबंधों की संख्या \(2^6=64\) होती है। परीक्षा में पहले \(A\times B\) के अवयव गिनें।