यदि \(A=\{1,2,3,4,5\}\) है, तो (\mathcal{P}(A)) में ऐसे subsets कितने हैं जिनका cardinality (2) से अधिक है?

If \(A=\{1,2,3,4,5\}\), how many subsets in (\mathcal{P}(A)) have cardinality greater than (2)?

Explanation opens after your attempt
Correct Answer

A. (16)

Step 1

Concept

Total subsets are \(2^5=32\), and those of sizes (0,1,2) are (1+5+10=16), so the answer is (16). In exams, use complement counting.

Step 2

Why this answer is correct

The correct answer is A. (16). Total subsets are \(2^5=32\), and those of sizes (0,1,2) are (1+5+10=16), so the answer is (16). In exams, use complement counting.

Step 3

Exam Tip

कुल \(2^5=32\) subsets हैं और sizes (0,1,2) वाले (1+5+10=16) हैं, इसलिए उत्तर (16) है। परीक्षा में complement counting करें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{1,2,3,4,5\}\) है, तो (\mathcal{P}(A)) में ऐसे subsets कितने हैं जिनका cardinality (2) से अधिक है? / If \(A=\{1,2,3,4,5\}\), how many subsets in (\mathcal{P}(A)) have cardinality greater than (2)?

Correct Answer: A. (16). Explanation: कुल \(2^5=32\) subsets हैं और sizes (0,1,2) वाले (1+5+10=16) हैं, इसलिए उत्तर (16) है। परीक्षा में complement counting करें। / Total subsets are \(2^5=32\), and those of sizes (0,1,2) are (1+5+10=16), so the answer is (16). In exams, use complement counting.

Which concept should I revise for this Mathematics MCQ?

Total subsets are \(2^5=32\), and those of sizes (0,1,2) are (1+5+10=16), so the answer is (16). In exams, use complement counting.

What exam hint can help solve this Mathematics question?

कुल \(2^5=32\) subsets हैं और sizes (0,1,2) वाले (1+5+10=16) हैं, इसलिए उत्तर (16) है। परीक्षा में complement counting करें।