यदि \(A=\{1,2,3,4,5\}\), तो (\mathcal{P}(A)) के कितने तत्वों में (2) और (5) दोनों होंगे लेकिन (1) नहीं होगा?
If \(A=\{1,2,3,4,5\}\), how many elements of (\mathcal{P}(A)) contain both (2) and (5) but not (1)?
Explanation opens after your attempt
Correct Answer
B. (4)
Concept
(2,5) are fixed and (1) is forbidden. The remaining (3,4) are free, so there are \(2^2=4\) subsets.
Why this answer is correct
The correct answer is B. (4). (2,5) are fixed and (1) is forbidden. The remaining (3,4) are free, so there are \(2^2=4\) subsets.
Exam Tip
(2,5) निश्चित हैं और (1) निषिद्ध है। शेष (3,4) स्वतंत्र हैं, इसलिए \(2^2=4\) उपसमुच्चय होंगे।
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