यदि \(A=\{0,1,2,3,4\}\), तो (\mathcal{P}(A)) के कितने तत्वों में (0) होगा और उनका आकार विषम होगा?
If \(A=\{0,1,2,3,4\}\), how many elements of (\mathcal{P}(A)) contain (0) and have odd size?
Explanation opens after your attempt
Correct Answer
C. (8)
Concept
After fixing (0), an even number of the remaining four elements must be chosen. The count is \(\binom{4}{0}+\binom{4}{2}+\binom{4}{4}=8\).
Why this answer is correct
The correct answer is C. (8). After fixing (0), an even number of the remaining four elements must be chosen. The count is \(\binom{4}{0}+\binom{4}{2}+\binom{4}{4}=8\).
Exam Tip
(0) को निश्चित रखने पर शेष चार तत्वों में से सम संख्या चुननी होगी। संख्या \(\binom{4}{0}+\binom{4}{2}+\binom{4}{4}=8\) है।
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