सिस्टम \(x \ge 0\), \(y \ge 0\), \(2x+y \le 8\), \(x+2y \le 8\) के समाधान क्षेत्र के कितने शीर्ष हैं?

How many vertices are in the solution region of \(x \ge 0\), \(y \ge 0\), \(2x+y \le 8\), and \(x+2y \le 8\)?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

The vertices are ((0,0)), ((4,0)), (\left\(\frac{8}{3},\frac{8}{3}\right\)), and ((0,4)). List all valid corners in order.

Step 2

Why this answer is correct

The correct answer is B. (4). The vertices are ((0,0)), ((4,0)), (\left\(\frac{8}{3},\frac{8}{3}\right\)), and ((0,4)). List all valid corners in order.

Step 3

Exam Tip

शीर्ष ((0,0)), ((4,0)), (\left\(\frac{8}{3},\frac{8}{3}\right\)), और ((0,4)) हैं। सभी वैध कोनों को क्रम से सूचीबद्ध करें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

सिस्टम \(x \ge 0\), \(y \ge 0\), \(2x+y \le 8\), \(x+2y \le 8\) के समाधान क्षेत्र के कितने शीर्ष हैं? / How many vertices are in the solution region of \(x \ge 0\), \(y \ge 0\), \(2x+y \le 8\), and \(x+2y \le 8\)?

Correct Answer: B. (4). Explanation: शीर्ष ((0,0)), ((4,0)), (\left\(\frac{8}{3},\frac{8}{3}\right\)), और ((0,4)) हैं। सभी वैध कोनों को क्रम से सूचीबद्ध करें। / The vertices are ((0,0)), ((4,0)), (\left\(\frac{8}{3},\frac{8}{3}\right\)), and ((0,4)). List all valid corners in order.

Which concept should I revise for this Mathematics MCQ?

The vertices are ((0,0)), ((4,0)), (\left\(\frac{8}{3},\frac{8}{3}\right\)), and ((0,4)). List all valid corners in order.

What exam hint can help solve this Mathematics question?

शीर्ष ((0,0)), ((4,0)), (\left\(\frac{8}{3},\frac{8}{3}\right\)), और ((0,4)) हैं। सभी वैध कोनों को क्रम से सूचीबद्ध करें।