( \frac{(2n+3)!}{(2n-1)!} ) के विस्तार में कितने गुणक बचते हैं?
How many factors remain in the expansion of ( \frac{(2n+3)!}{(2n-1)!} )?
Explanation opens after your attempt
B. (4)
Concept
The expansion leaves ((2n+3)(2n+2)(2n+1)(2n)). Therefore there are (4) factors.
Why this answer is correct
The correct answer is B. (4). The expansion leaves ((2n+3)(2n+2)(2n+1)(2n)). Therefore there are (4) factors.
Exam Tip
विस्तार में ((2n+3)(2n+2)(2n+1)(2n)) बचता है। इसलिए कुल (4) गुणक हैं।
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