समुच्चय \({x \in \mathbb{Z}:x^2<10}\) में कितने तत्व हैं?

How many elements are in the set \({x \in \mathbb{Z}:x^2<10}\)?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

The integers satisfying \(x^2<10\) are (-3,-2,-1,0,1,2,3).

Step 2

Why this answer is correct

Their squares are less than (10).

Step 3

Exam Tip

The set is finite and has (7) elements. चरण 1: \(x^2<10\) के लिए पूर्णांक (x=-3,-2,-1,0,1,2,3) मिलते हैं। चरण 2: इनके वर्ग (10) से छोटे हैं। चरण 3: इसलिए यह सांत समुच्चय है और इसमें (7) तत्व हैं।

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समुच्चय \({x \in \mathbb{Z}:x^2<10}\) में कितने तत्व हैं? / How many elements are in the set \({x \in \mathbb{Z}:x^2<10}\)?

Correct Answer: C. (7). Explanation: चरण 1: \(x^2<10\) के लिए पूर्णांक (x=-3,-2,-1,0,1,2,3) मिलते हैं। चरण 2: इनके वर्ग (10) से छोटे हैं। चरण 3: इसलिए यह सांत समुच्चय है और इसमें (7) तत्व हैं। / Step 1: The integers satisfying \(x^2<10\) are (-3,-2,-1,0,1,2,3). Step 2: Their squares are less than (10). Step 3: The set is finite and has (7) elements.

Which concept should I revise for this Mathematics MCQ?

The integers satisfying \(x^2<10\) are (-3,-2,-1,0,1,2,3).

What exam hint can help solve this Mathematics question?

The set is finite and has (7) elements. चरण 1: \(x^2<10\) के लिए पूर्णांक (x=-3,-2,-1,0,1,2,3) मिलते हैं। चरण 2: इनके वर्ग (10) से छोटे हैं। चरण 3: इसलिए यह सांत समुच्चय है और इसमें (7) तत्व हैं।