शब्द (CALCULUS) की कितनी भिन्न व्यवस्थाएं बनेंगी?
How many distinct arrangements can be formed from the letters of (CALCULUS)?
Explanation opens after your attempt
A. (10080)
Concept
There are (8) letters with (C,L,U) each repeated twice, so the count is (8!/(2!2!2!)). Identifying repetitions is the key step.
Why this answer is correct
The correct answer is A. (10080). There are (8) letters with (C,L,U) each repeated twice, so the count is (8!/(2!2!2!)). Identifying repetitions is the key step.
Exam Tip
(8) अक्षरों में (C,L,U) दो-दो बार हैं, इसलिए संख्या (8!/(2!2!2!)) है। आवृत्तियों को पहचानना मुख्य कदम है।
Login to save your score, XP, coins and progress.
