अंकों (2,4,6,8,9) से बिना पुनरावृत्ति कितनी (3)-अंकीय विषम संख्याएँ बनेंगी?
How many (3)-digit odd numbers can be formed from digits (2,4,6,8,9) without repetition?
Explanation opens after your attempt
C. (12)
Concept
Only (9) can be in the units place, and the other two places can be filled in \(4\times3=12\) ways. For odd numbers, check the units place first.
Why this answer is correct
The correct answer is C. (12). Only (9) can be in the units place, and the other two places can be filled in \(4\times3=12\) ways. For odd numbers, check the units place first.
Exam Tip
इकाई स्थान पर केवल (9) आएगा और बाकी दो स्थान \(4\times3=12\) तरीकों से भरेंगे। odd number में इकाई स्थान पहले देखें।
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