अंकों (1,3,5,7,9) से बिना पुनरावृत्ति (3) अंकों की कितनी संख्याएं बनेंगी?

How many (3)-digit numbers can be formed from (1,3,5,7,9) without repetition?

Explanation opens after your attempt
Correct Answer

A. (60)

Step 1

Concept

There are (5,4,3) choices for the three positions. The total is \(5\cdot4\cdot3=60\).

Step 2

Why this answer is correct

The correct answer is A. (60). There are (5,4,3) choices for the three positions. The total is \(5\cdot4\cdot3=60\).

Step 3

Exam Tip

तीन स्थानों पर क्रम से (5,4,3) विकल्प हैं। कुल \(5\cdot4\cdot3=60\) है।

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Mathematics Answer, Explanation and Revision Hints

अंकों (1,3,5,7,9) से बिना पुनरावृत्ति (3) अंकों की कितनी संख्याएं बनेंगी? / How many (3)-digit numbers can be formed from (1,3,5,7,9) without repetition?

Correct Answer: A. (60). Explanation: तीन स्थानों पर क्रम से (5,4,3) विकल्प हैं। कुल \(5\cdot4\cdot3=60\) है। / There are (5,4,3) choices for the three positions. The total is \(5\cdot4\cdot3=60\).

Which concept should I revise for this Mathematics MCQ?

There are (5,4,3) choices for the three positions. The total is \(5\cdot4\cdot3=60\).

What exam hint can help solve this Mathematics question?

तीन स्थानों पर क्रम से (5,4,3) विकल्प हैं। कुल \(5\cdot4\cdot3=60\) है।