अंकों (3,6,9) से पुनरावृत्ति की अनुमति होने पर कितनी (2)-अंकीय संख्याएँ बनेंगी?
How many (2)-digit numbers can be formed from digits (3,6,9) if repetition is allowed?
Explanation opens after your attempt
A. (9)
Concept
There are (3) choices at both places, so \(3^2=9\). With repetition allowed, choices remain the same.
Why this answer is correct
The correct answer is A. (9). There are (3) choices at both places, so \(3^2=9\). With repetition allowed, choices remain the same.
Exam Tip
दोनों स्थानों पर (3) विकल्प हैं इसलिए \(3^2=9\)। repetition allowed हो तो विकल्प वही रहते हैं।
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