असमानताओं \(x+y\leq m\), \(x\geq 3\), \(y\geq 4\) का हल-क्षेत्र अरिक्त होने के लिए (m) की सही शर्त क्या है?
For the solution region of \(x+y\leq m\), \(x\geq 3\), and \(y\geq 4\) to be non-empty, what is the correct condition on (m)?
Explanation opens after your attempt
Correct Answer
A. \(m\geq 7\)
Concept
The minimum value of (x+y) at ((3,4)) is (7). Hence \(m\geq 7\) is required for a solution.
Why this answer is correct
The correct answer is A. \(m\geq 7\). The minimum value of (x+y) at ((3,4)) is (7). Hence \(m\geq 7\) is required for a solution.
Exam Tip
न्यूनतम (x+y) बिंदु ((3,4)) पर (7) है। इसलिए हल मिलने के लिए \(m\geq 7\) होना जरूरी है।
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