\(A=\{1,2,3\}\) पर \(R=\{(a,b):a\ne b\}\) के लिए सही विकल्प चुनिए।

For \(R=\{(a,b):a\ne b\}\) on \(A=\{1,2,3\}\), choose the correct option.

Explanation opens after your attempt
Correct Answer

A. सममित पर संकर्मक नहींSymmetric but not transitive

Step 1

Concept

If \(a\ne b\), then \(b\ne a\) also. But ((1,2)) and ((2,1)) would require ((1,1)), which is absent.

Step 2

Why this answer is correct

The correct answer is A. सममित पर संकर्मक नहीं / Symmetric but not transitive. If \(a\ne b\), then \(b\ne a\) also. But ((1,2)) and ((2,1)) would require ((1,1)), which is absent.

Step 3

Exam Tip

यदि \(a\ne b\), तो \(b\ne a\) भी है। पर ((1,2)) और ((2,1)) से ((1,1)) चाहिए जो नहीं है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

\(A=\{1,2,3\}\) पर \(R=\{(a,b):a\ne b\}\) के लिए सही विकल्प चुनिए। / For \(R=\{(a,b):a\ne b\}\) on \(A=\{1,2,3\}\), choose the correct option.

Correct Answer: A. सममित पर संकर्मक नहीं / Symmetric but not transitive. Explanation: यदि \(a\ne b\), तो \(b\ne a\) भी है। पर ((1,2)) और ((2,1)) से ((1,1)) चाहिए जो नहीं है। / If \(a\ne b\), then \(b\ne a\) also. But ((1,2)) and ((2,1)) would require ((1,1)), which is absent.

Which concept should I revise for this Mathematics MCQ?

If \(a\ne b\), then \(b\ne a\) also. But ((1,2)) and ((2,1)) would require ((1,1)), which is absent.

What exam hint can help solve this Mathematics question?

यदि \(a\ne b\), तो \(b\ne a\) भी है। पर ((1,2)) और ((2,1)) से ((1,1)) चाहिए जो नहीं है।