किसी समुच्चय (A) के लिए (n(\mathcal{P}(\mathcal{P}(A)))=16) है, तो (n(A)) कितना है?

For a set (A), (n(\mathcal{P}(\mathcal{P}(A)))=16). What is (n(A))?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

Here \(2^{2^{n(A)}}=16=2^4\), so \(2^{n(A)}=4\) and (n(A)=2). Apply the power set formula twice.

Step 2

Why this answer is correct

The correct answer is B. (2). Here \(2^{2^{n(A)}}=16=2^4\), so \(2^{n(A)}=4\) and (n(A)=2). Apply the power set formula twice.

Step 3

Exam Tip

यहां \(2^{2^{n(A)}}=16=2^4\), इसलिए \(2^{n(A)}=4\) और (n(A)=2)। घात समुच्चय पर घात समुच्चय में दो बार सूत्र लगाएं।

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Mathematics Answer, Explanation and Revision Hints

किसी समुच्चय (A) के लिए (n(\mathcal{P}(\mathcal{P}(A)))=16) है, तो (n(A)) कितना है? / For a set (A), (n(\mathcal{P}(\mathcal{P}(A)))=16). What is (n(A))?

Correct Answer: B. (2). Explanation: यहां \(2^{2^{n(A)}}=16=2^4\), इसलिए \(2^{n(A)}=4\) और (n(A)=2)। घात समुच्चय पर घात समुच्चय में दो बार सूत्र लगाएं। / Here \(2^{2^{n(A)}}=16=2^4\), so \(2^{n(A)}=4\) and (n(A)=2). Apply the power set formula twice.

Which concept should I revise for this Mathematics MCQ?

Here \(2^{2^{n(A)}}=16=2^4\), so \(2^{n(A)}=4\) and (n(A)=2). Apply the power set formula twice.

What exam hint can help solve this Mathematics question?

यहां \(2^{2^{n(A)}}=16=2^4\), इसलिए \(2^{n(A)}=4\) और (n(A)=2)। घात समुच्चय पर घात समुच्चय में दो बार सूत्र लगाएं।