फलन (f(x)=\sqrt{x-2-16}) का परिसर चुनिए।
Choose the range of (f(x)=\sqrt{x-2-16}).
Explanation opens after your attempt
Correct Answer
A. \([0,\infty\))
Concept
On the domain, \(x^2-16\ge 0\) and the minimum square-root value is (0). For large (|x|), the value grows without bound.
Why this answer is correct
The correct answer is A. \([0,\infty\)). On the domain, \(x^2-16\ge 0\) and the minimum square-root value is (0). For large (|x|), the value grows without bound.
Exam Tip
प्रांत में \(x^2-16\ge 0\) और वर्गमूल का न्यूनतम मान (0) है। बड़े (|x|) पर मान असीमित बढ़ता है।
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