(12)-भुज के शीर्षों में से (4) शीर्ष चुनने हैं ताकि कोई दो चुने हुए शीर्ष आसन्न न हों। कितने चयन संभव हैं?

Choose (4) vertices of a (12)-gon so that no two chosen vertices are adjacent. How many selections are possible?

Explanation opens after your attempt
Correct Answer

D. (105)

Step 1

Concept

The circular non-adjacent selection formula is \(\frac{n}{n-r},{}^{n-r}C_{r}\). Here \(\frac{12}{8}\times{}^{8}C_{4}=105\).

Step 2

Why this answer is correct

The correct answer is D. (105). The circular non-adjacent selection formula is \(\frac{n}{n-r},{}^{n-r}C_{r}\). Here \(\frac{12}{8}\times{}^{8}C_{4}=105\).

Step 3

Exam Tip

वृत्तीय गैर-आसन्न चयन का सूत्र \(\frac{n}{n-r},{}^{n-r}C_{r}\) है। यहां \(\frac{12}{8}\times{}^{8}C_{4}=105\)।

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Mathematics Answer, Explanation and Revision Hints

(12)-भुज के शीर्षों में से (4) शीर्ष चुनने हैं ताकि कोई दो चुने हुए शीर्ष आसन्न न हों। कितने चयन संभव हैं? / Choose (4) vertices of a (12)-gon so that no two chosen vertices are adjacent. How many selections are possible?

Correct Answer: D. (105). Explanation: वृत्तीय गैर-आसन्न चयन का सूत्र \(\frac{n}{n-r},{}^{n-r}C_{r}\) है। यहां \(\frac{12}{8}\times{}^{8}C_{4}=105\)। / The circular non-adjacent selection formula is \(\frac{n}{n-r},{}^{n-r}C_{r}\). Here \(\frac{12}{8}\times{}^{8}C_{4}=105\).

Which concept should I revise for this Mathematics MCQ?

The circular non-adjacent selection formula is \(\frac{n}{n-r},{}^{n-r}C_{r}\). Here \(\frac{12}{8}\times{}^{8}C_{4}=105\).

What exam hint can help solve this Mathematics question?

वृत्तीय गैर-आसन्न चयन का सूत्र \(\frac{n}{n-r},{}^{n-r}C_{r}\) है। यहां \(\frac{12}{8}\times{}^{8}C_{4}=105\)।