(9) अंकों \(1,2,\ldots,9\) में से (4) अंक चुनने हैं जिनका योग सम हो। कितने चयन हैं?

Choose (4) digits from \(1,2,\ldots,9\) such that their sum is even. How many selections are there?

Explanation opens after your attempt
Correct Answer

C. (64)

Step 1

Concept

For an even sum, the number of odd digits must be (0,2,4). Count \(^{4}C_{4}+^{5}C_{2}{}^{4}C_{2}+^{5}C_{4}=66\).

Step 2

Why this answer is correct

The correct answer is C. (64). For an even sum, the number of odd digits must be (0,2,4). Count \(^{4}C_{4}+^{5}C_{2}{}^{4}C_{2}+^{5}C_{4}=66\).

Step 3

Exam Tip

सम योग के लिए विषम अंकों की संख्या (0,2,4) होनी चाहिए। गणना \(^{4}C_{4}+^{5}C_{2}{}^{4}C_{2}+^{5}C_{4}=66\) है।

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Mathematics Answer, Explanation and Revision Hints

(9) अंकों \(1,2,\ldots,9\) में से (4) अंक चुनने हैं जिनका योग सम हो। कितने चयन हैं? / Choose (4) digits from \(1,2,\ldots,9\) such that their sum is even. How many selections are there?

Correct Answer: C. (64). Explanation: सम योग के लिए विषम अंकों की संख्या (0,2,4) होनी चाहिए। गणना \(^{4}C_{4}+^{5}C_{2}{}^{4}C_{2}+^{5}C_{4}=66\) है। / For an even sum, the number of odd digits must be (0,2,4). Count \(^{4}C_{4}+^{5}C_{2}{}^{4}C_{2}+^{5}C_{4}=66\).

Which concept should I revise for this Mathematics MCQ?

For an even sum, the number of odd digits must be (0,2,4). Count \(^{4}C_{4}+^{5}C_{2}{}^{4}C_{2}+^{5}C_{4}=66\).

What exam hint can help solve this Mathematics question?

सम योग के लिए विषम अंकों की संख्या (0,2,4) होनी चाहिए। गणना \(^{4}C_{4}+^{5}C_{2}{}^{4}C_{2}+^{5}C_{4}=66\) है।