ग्राफ (y=|x|) और (y=3-x) किस बिंदु पर मिलते हैं?
At which point do the graphs (y=|x|) and (y=3-x) meet?
Explanation opens after your attempt
A. (\left\(\frac{3}{2},\frac{3}{2}\right\))
Concept
For \(x\ge 0\), put (|x|=x), so (x=3-x) gives \(x=\frac{3}{2}\). Hence the intersection is (\left\(\frac{3}{2},\frac{3}{2}\right\)).
Why this answer is correct
The correct answer is A. (\left\(\frac{3}{2},\frac{3}{2}\right\)). For \(x\ge 0\), put (|x|=x), so (x=3-x) gives \(x=\frac{3}{2}\). Hence the intersection is (\left\(\frac{3}{2},\frac{3}{2}\right\)).
Exam Tip
\(x\ge 0\) पर (|x|=x) रखकर (x=3-x) से \(x=\frac{3}{2}\) मिलता है। इसलिए प्रतिच्छेद (\left\(\frac{3}{2},\frac{3}{2}\right\)) है।
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