ग्राफ (y=|x|) और (y=3-x) किस बिंदु पर मिलते हैं?

At which point do the graphs (y=|x|) and (y=3-x) meet?

Explanation opens after your attempt
Correct Answer

A. (\left\(\frac{3}{2},\frac{3}{2}\right\))

Step 1

Concept

For \(x\ge 0\), put (|x|=x), so (x=3-x) gives \(x=\frac{3}{2}\). Hence the intersection is (\left\(\frac{3}{2},\frac{3}{2}\right\)).

Step 2

Why this answer is correct

The correct answer is A. (\left\(\frac{3}{2},\frac{3}{2}\right\)). For \(x\ge 0\), put (|x|=x), so (x=3-x) gives \(x=\frac{3}{2}\). Hence the intersection is (\left\(\frac{3}{2},\frac{3}{2}\right\)).

Step 3

Exam Tip

\(x\ge 0\) पर (|x|=x) रखकर (x=3-x) से \(x=\frac{3}{2}\) मिलता है। इसलिए प्रतिच्छेद (\left\(\frac{3}{2},\frac{3}{2}\right\)) है।

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Mathematics Answer, Explanation and Revision Hints

ग्राफ (y=|x|) और (y=3-x) किस बिंदु पर मिलते हैं? / At which point do the graphs (y=|x|) and (y=3-x) meet?

Correct Answer: A. (\left\(\frac{3}{2},\frac{3}{2}\right\)). Explanation: \(x\ge 0\) पर (|x|=x) रखकर (x=3-x) से \(x=\frac{3}{2}\) मिलता है। इसलिए प्रतिच्छेद (\left\(\frac{3}{2},\frac{3}{2}\right\)) है। / For \(x\ge 0\), put (|x|=x), so (x=3-x) gives \(x=\frac{3}{2}\). Hence the intersection is (\left\(\frac{3}{2},\frac{3}{2}\right\)).

Which concept should I revise for this Mathematics MCQ?

For \(x\ge 0\), put (|x|=x), so (x=3-x) gives \(x=\frac{3}{2}\). Hence the intersection is (\left\(\frac{3}{2},\frac{3}{2}\right\)).

What exam hint can help solve this Mathematics question?

\(x\ge 0\) पर (|x|=x) रखकर (x=3-x) से \(x=\frac{3}{2}\) मिलता है। इसलिए प्रतिच्छेद (\left\(\frac{3}{2},\frac{3}{2}\right\)) है।