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What is the range of the function y = √(16 − x²)?फलन y = √(16 − x²) का परास क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: [0, 4][0, 4]
The square root ensures y ≥ 0. Also, 16 − x² ≤ 16, so y ≤ 4. The value 4 occurs at x = 0, and 0 occurs at x = ±4. Thus the range is [0, 4].वर्गमूल के कारण y ≥ 0 है। साथ ही, 16 − x² ≤ 16, इसलिए y ≤ 4। x = 0 पर y = 4 और x = ±4 पर y = 0 मिलता है। अतः परास [0, 4] है।
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