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What is the domain of the function y = √(16 − x²)?फलन y = √(16 − x²) का डोमेन (परिभाषा-क्षेत्र) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: [−4, 4][−4, 4]
The radicand must be non-negative: 16 − x² ≥ 0. Hence x² ≤ 16, which gives −4 ≤ x ≤ 4. The endpoints are included because the radicand is zero there, so the domain is [−4, 4].मूलांक गैर-ऋणात्मक होना चाहिए: 16 − x² ≥ 0। इससे x² ≤ 16, अर्थात् −4 ≤ x ≤ 4 मिलता है। दोनों सिरों पर मूलांक शून्य है, इसलिए वे शामिल हैं और डोमेन [−4, 4] है।
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