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What is the domain of the function \(f(x)=\sqrt{2x+6}\) over the real numbers?

Answer and explanation

Correct answer: \(x\ge -3\)

For a square root to be real, the expression inside the radical must be non-negative: \(2x+6\ge 0\). Thus, \(2x\ge -6\), giving \(x\ge -3\). Option B reverses the inequality, while option D includes real numbers for which the radicand is negative. Exam tip: For a square-root function, set the radicand greater than or equal to zero to find the domain.

Related tags

Standard-FunctionsSquare-Root-FunctionDomainReal-NumbersReal Valued FunctionsTheir Domain And RangeReal Valued Functions Their Domain And RangeRelations And FunctionsMathematics

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