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What is the value of the function \(f(x)=\{x+1\}\) at \(x=2.3\)? Here, \(\{y\}\) denotes the fractional part of \(y\).फलन \(f(x)=\{x+1\}\) का \(x=2.3\) पर मान क्या है? यहाँ \(\{y\}\) से तात्पर्य \(y\) के भिन्नात्मक भाग से है।
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 0.30.3
Substituting \(x=2.3\), we get \(f(2.3)=\{2.3+1\}=\{3.3\}\). The fractional part of \(3.3\) is \(0.3\), obtained after removing its integer part, \(3\). Hence, option A is correct. Exam tip: use \(\{y\}=y-\lfloor y\rfloor\); therefore, \(\{3.3\}=3.3-3=0.3\). The value \(3.3\) itself is not the fractional part.\(x=2.3\) रखने पर \(f(2.3)=\{2.3+1\}=\{3.3\}\)। संख्या \(3.3\) का भिन्नात्मक भाग \(0.3\) है, क्योंकि पूर्णांक भाग \(3\) हटाने पर \(0.3\) बचता है। इसलिए सही उत्तर A है। परीक्षा में याद रखें: \(\{y\}=y-\lfloor y\rfloor\)। अतः \(\{3.3\}=3.3-3=0.3\), जबकि \(3.3\) पूरी संख्या का मान है, भिन्नात्मक भाग नहीं।
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