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For the function \(f(x)=\operatorname{sgn}(x+1)\), what is its value at \(x=-1\)?

Answer and explanation

Correct answer: 0

When \(x=-1\), we get \(x+1=0\). For the signum function, \(\operatorname{sgn}(0)=0\); hence, \(f(-1)=0\). Exam tip: \(\operatorname{sgn}(t)\) equals 1 for \(t>0\), 0 for \(t=0\), and -1 for \(t<0\). Therefore, 1 and -1 are incorrect here, and the function is defined at \(x=-1\).

Related tags

Standard-FunctionsSignum-FunctionRelations-And-FunctionsReal Valued FunctionsTheir Domain And RangeReal Valued Functions Their Domain And RangeRelations And FunctionsMathematicsClass 11 Mcq

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