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What is the domain of (f(x)=\sqrt{\log_{\frac{1}{4}}(9-x)})?फलन (f(x)=\sqrt{\log_{\frac{1}{4}}(9-x)}) का प्रांत क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( [8,9) )( [8,9) )
The square root needs (\log_{\frac{1}{4}}(9-x)\ge 0) and (9-x>0). Since the base (\frac{1}{4}<1), (0<9-x\le 1), so the domain is ([8,9)).वर्गमूल के लिए (\log_{\frac{1}{4}}(9-x)\ge 0) और (9-x>0) चाहिए। आधार (\frac{1}{4}<1) होने से (0<9-x\le 1), इसलिए प्रांत ([8,9)) है।
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