0 reads0 ratings0 helpful
What is the domain of (f(x)=\sqrt{1-\frac{1}{x^2}})?फलन (f(x)=\sqrt{1-\frac{1}{x^2}}) का प्रांत क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( (-\infty,-1]\cup[1,\infty) )( (-\infty,-1]\cup[1,\infty) )
The square root needs (1-\frac{1}{x^2}\ge 0) and (x\ne 0). This gives (x^2\ge 1), so (|x|\ge 1).वर्गमूल के लिए (1-\frac{1}{x^2}\ge 0) और (x\ne 0) चाहिए। इससे (x^2\ge 1), यानी (|x|\ge 1) मिलता है।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
