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What is the range of (f(x)=\frac{\sqrt{x+3}}{\sqrt{2-x}})?फलन (f(x)=\frac{\sqrt{x+3}}{\sqrt{2-x}}) का परिसर क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( [0,\infty) )( [0,\infty) )
The function is (\sqrt{\frac{x+3}{2-x}}), where the fraction takes all values in ([0,\infty)). Hence the square root range is also ([0,\infty)).फलन (\sqrt{\frac{x+3}{2-x}}) है, जहां भिन्न ([0,\infty)) के सभी मान लेता है। इसलिए वर्गमूल का परिसर भी ([0,\infty)) है।
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