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What is the domain of (f(x)=\sqrt{\frac{x^2-1}{4-x^2}})?फलन (f(x)=\sqrt{\frac{x^2-1}{4-x^2}}) का प्रांत क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( (-2,-1]\cup[1,2) )( (-2,-1]\cup[1,2) )
The square root needs (\frac{x^2-1}{4-x^2}\ge 0) and (x\ne\pm2). A sign check gives ((-2,-1]\cup[1,2)).वर्गमूल के अंदर (\frac{x^2-1}{4-x^2}\ge 0) और (x\ne\pm2) चाहिए। संकेत जांच से ((-2,-1]\cup[1,2)) मिलता है।
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